In the given figure, DE || BC, find the
values of x, y and z.
And what is tge property that us used in this question?
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Answered by
3
Answer:
40°+z+55°=180°
95°+z=180°
z=180°-95°
z=85°
Now see in EACB
y=55°. (alternate interior angles)
Now in DABC
x=40°. ( alternate interior angles)
Answered by
3
Answer:
x = 40°,y = 55°,z = 85°
Step-by-step explanation:
Given that:
A triangle ABC. Through a line DE parallel to BC.
To find:
the value of x,y an z
Solution:
X = 40° [Alt. int. ∠s]
Y = 55° [Alt. int. ∠s]
Now,
x°+y°+z° = 180°
40°+55°+x° = 180°
95°+x° = 180°
x° = 180°-95°
x =85°
So the value of x = 40°,y = 55°, z = 85°
Check:
Sum of interior angle of a triangle = 180°
x+y+x = 180°
40°+55°+85° = 180°
180° = 180° ans.
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