Question

in the given figure DE || BC find x​

Answer 1

$\huge\underline\mathfrak{Answer:}$

$\huge\boxed{x=90°}$

____________________

$\huge\underline\mathfrak{Explanation:}$

Given : DE || BC

To find : value of x.

Solution : If DE || BC

Therefore, angle AED = angle ACB ( corresponding angles )

Angle AED = 20°

$\therefore$ angle ACB = 20°

Now, In ∆ABC

Angle A + Angle B + Angle C = 180° ( By angle sum property )

x + 70° + 20° = 180°

=> x + 90° = 180°

=> x = 180° - 90°

=> x = 90° ( required answer )

Answer 2

Answer:

Step by-step explanation:

If DE|| BC

Then angle DBC = angle ADE (corr.angles)

So, angle ADE =70

In triangle ADE ,by angle sum prop.

Angle ADE+ angle DAE+ angle AED =180

70 + X + 20=180

90 + X=180

180-90=X

X=90