Question

in the given figure,DE||BC,find x​

Answer 1

Answer:

90°

Step-by-step explanation:

Since DE II BC, considering AB as transversal,

Angle ADE = Angle DBC

=> Angle ADE = 70°

In triangle ADE, Angle ADE = 70°, Angle AED= 20°.

Thus, by angle sum property of triangle,

Angle ADE + Angle AED + Angle DAE = 180°

=> 70° + 20° + x = 180°

=> x = 180° - 70° - 20°

=> x = 90°

Answer 2

Answer:

90°

Step-by-step explanation:

Since DE II BC

Angle ADE =Angle ABC = 70° (By alternate angle)

In triangle ABC

Angle A+B+c =180°

Angle A= 90°