Question

In the given figure DE//BC. if AD =x cm ,DB=x-3,AE=x+3 and EC=x-2,find the value of x.

Answer 1

Step-by-step explanation:

$we \: know \: \\ \frac{ad}{db} = \frac{ae}{ec} \\ \frac{x}{x - 3} = \frac{x + 3}{x - 2} \\ x(x - 2) = (x + 3)(x - 3) \\ {x}^{2} - 2x = {x}^{2} - 9 \\ - 2x = - 9 \\ 9 = 2x \\ x = 4.5cm$