Question

In the given figure,
DE || BC. If DE : BC = 3:5, find
ar (A ADE)
ar (trap. Bced)​

Answer 1

Answer:

Here ∆ ADE ~ ∆ABC (A-A-A)

We know that if two triangle s are similar then ratio of their area equal to square of corresponding sides.

area ∆ ADE/area∆ABC= DE^2/BC^2

SO, area of ∆ADE= (9/25)area ∆ABC

Next, area of trapezium BCDE = area∆ABC- area ∆ADE = (16/25)area∆ABC

Answer 2

Answer:

eei.. enthokke vishesham

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