In the given figure, DE || BC,<ADE = 70° and <BAC = 50°, Then angle <BCA =____
who give me correct and only correct answer, I will mark you brainliest and also give you 50 points...but only on correct answer...
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Answer:
60°
Step-by-step explanation:
In triangle ADE
ANGLE ADE + ANGLE DAE + ANGLE AED = 180°
70+50+AED = 180
AED= 60°
ANGLE AED = ANGLE BCA ( Alternate interior angles)
ANGLE BCA = 60°
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