Question

In the given figure, DE || BC,<ADE = 70° and <BAC = 50°, Then angle <BCA =____

who give me correct and only correct answer, I will mark you brainliest and also give you 50 points...but only on correct answer...​

Answer 1

$\huge \mathscr{\orange {\underline{\pink{\underline {Answer:-}}}}}$

Since,

DE || BC

∠ABC = ∠ADE

∠ABC = 70°

So,

By Angle Sum Property of Triangle.

∠BAC + ∠ABC + ∠BCA = 180°

50° + 70° + ∠BCA = 180°

120° + ∠BCA = 180°

∠BCA = 180° - 120°

∠BCA = 60°.

Answer 2

Answer:

60°

Step-by-step explanation:

In Triangle ADE,

angle AED=180°-70°-50°=60°.

DEIIBC,

AED=BCA (Corresponding angles)

BCA=60°.