Math, asked by prog00588, 14 hours ago

In the given figure, DE = DF. Find ∠D,​

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Answered by Anonymous
1

Answer:

In triangle ABC

D is the midpoint of BC

DE perpendicular to AB

And DF perpendicular to AC

DE=DF

To prove:

Triangle ABC is an isosceles triangle

Proof:

In the right angles triangle BED and CDF

Hypotenuse BD=DC ( because D is a midpoint )

Side DF=DE ( given)

△BED≅CDF ( RHS axiom)

∠C=∠B

AB=AC ( sides opposite to equal angles

△ABC is an isosceles triangle

Answered by singhramkrishna97
3

Step-by-step explanation:

DE=DF

angle DEF = angle DFE. = x

angle DFE + 130 = 180

angle DFE = 50

IN TRIANGLE. DEF

DEF + DFE + D =180

50 +50 +D=180

D =80

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