in the given figure.,DE=EA.prove that AC+BC>BD
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Answer:
AC + BC > BD
Step-by-step explanation:
in Δ BDE
BE + DE > BD ( sum of two sides > third side)
DE = EA given
=> BE + EA > BD
=> AB > BD
in Δ ABC
AC + BC > AB ( sum of two sides > third side)
while AB > BD
=> AC + BC > AB > BD
=> AC + BC > BD
QED
Proved
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