Question

in the given figure.,DE=EA.prove that AC+BC>BD​

Answer 1

Answer:

AC + BC  > BD

Step-by-step explanation:

in Δ BDE

BE + DE  > BD  ( sum of two sides > third side)

DE = EA  given

=> BE + EA > BD

=> AB  > BD

in Δ ABC

AC + BC  > AB     ( sum of two sides > third side)

while AB > BD

=> AC + BC  > AB    > BD

=> AC + BC  > BD

QED

Proved