In the given figure DE II BC, if AD = x, DB=x-2, AE=x+2 and EC=x-1 then find the value of x.
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In Δ ABC, DE ∥ BC
∴ AD / DB = AC / EC
(By basic proportionality theorem)
⇒x−2x=x−1x+2
⇒x(x−1)=(x+2)(x−2)
⇒x2−x=x2−4
⇒x=4.
hope it helps u
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