Question

In the given figure de is parallel to bc and ad equal to 1 cm bd equal to 2cm .what is the ratio

Answer 1

Heya....

Here's your answer...

Since DE || BC, by Thales theorem AD/DB = AE/EC Therefore, both AD/DB and AE/EC = 1: 2 So AD:AB = 1:3 or AB:AD = 3:1

The triangles are similar by SAS axiom. Hence the areas of the triangles are in the ratio of squares of corresponding sides.

Therefore, the ratio of area of Δ ABC to the area of Δ ADE = 3^2:1^2 = 9:1.

Thanks...!!!

XD

Sorry baby 'wink'

Answer 2

I hope this is helpful