Question

In the given figure De is parallel to BC and AD is equal to 1 cm BD is equals to 2 cm what is the ratio of the area of triangle ABC to area of triangle ade

Answer 1

It is given that AD = 1 cm, BD = 2 cm and DE || BC

In ∆ADE and ∆ABC,

∠ADE = ∠ABC (Corresponding angles)

∠A = ∠A [Common]

Therefore, by A.A. similar condition

∆ADE ~ ∆ABC

Ratio of areas of similar triangles is equal to the square of the ratio of the corresponding sides.

∴ fraction numerator ar left parenthesis increment ABC right parenthesis over denominator ar left parenthesis increment ADE right parenthesis end fraction equals AB squared over AD squared

please mark me as brainliest