Question

In the given figure DE is parallel to BC. If AD = x DB = x-2 AE = x+2 and EC = x-1 then calculate the value of x.​

Answer 1

Answer:

x=4

Step-by-step explanation:

Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.

To find: x

In △ABC, we have  

DE || BC

Therefore [By Thale's theorem]

AD/DB = AE/EC

AD × EC × = AE × DB

x(x-1) = (x-2)(x+2)

x2 - x = x2 - 4

x = 4

HOPE IT HELPS

Answer 2

Step-by-step explanation:

Triangle ABA, DE||BC, so by Basic Proportionality theorem, AD /DB = AE /EC

 

substituting the values, we get,

x/x-2 =x+2/x-1

 

By cross multiplying, we get,

 

x(x-1) =(x+2)(x-2)

 

x2 -x = x2 -4

 

x=4