in the given figure DE is parallel to BC if BC=12 cm and DE=6 cm find the ratio of area ADEto area OF TRIANGLE ABC
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Answered by
5
through are theorem we conclude that
ar(triangle ADE)/ar(triangle ABC)=whole sq of DE/whole sq of BC
6*6/12*12
=36/144
=1/4
ratio is 1 is to 4
ar(triangle ADE)/ar(triangle ABC)=whole sq of DE/whole sq of BC
6*6/12*12
=36/144
=1/4
ratio is 1 is to 4
Answered by
11
Step-by-step explanation:
area of triangle ADE/ area of triangle ABC = 1/4
Thus, the answer is 1:4
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