in the given figure De parallel to BC and AD:AB =1:3.If DE=1.5 cm,Then BC=
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Answer:
The given information is shown in the attached diagram.
DE∣∣BC
⟹∠ADE=∠ABC Corresponding angles
∠AED=∠ACB Corresponding angles
∠A is common to both the triangles.
∴ΔADE∼ΔABC by AAA similarity
⟹
AD
AB
=
AE
AC
AD
AB
−1=
AE
AC
−1
AD
BD
=
AE
CE
EC=1×
1.5
3
=2 cm
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