Question

In the
given figure DE parallel to BC find x where AD = x AE = 1.8 EC =5.4 DB = 7.2​

Answer 1

Answer:

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Answer 2

Given :

ABC is a right angled triangle

angle A = 90°

angle B : angle C = 4:5

To find:

angle B

angle C

Solution:

Let the common ratio be x .

Then ,

angle B = 4x

angle C = 5x

Applying angle sum property of a triangle ,

angle A + angle B + angle C = 180°

90° + 4x + 5x = 180°

90° + 9x = 180°

9x = 180° - 90°

9x = 90°

x = 90° / 9

x = 10

Therefore ,

angle B = 4 × 10 = 40°

angle B = 4 × 10 = 40° angle C = 5 × 10 = 50°

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\underline{ \underline{ \large{ \mathfrak{ \orange{some }\: \blue{basic }\: \green{concepts : }}}}}

somebasicconcepts:

A triangle in which one angle measures 90° is called a right angled triangle .

The side opposite to 90° angle is called hypotenuse . The other two sides are base and perpendicular .

In right angled triangle , hypotenuse² = Base² + Perpendicular ² (Pythagoras theorem)

According to angle sum property , sum of all angles in a triangle is 180° .