Question

In the given figure, DEFG is a square and BAC = 90°. Show that FG^2 = BG * FC
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Answer 1

Answer:

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Step-by-step explanation:

Given

A square EFGD & ∆ABC where angle BAC=90

In Square EFGD

GDE= FED= EFG=FGD = 90 and

DE = EF = FG= DG

In ∆BDG

DGB= 90

And ∆EFC,

EFC=90

From ∆ADE,∆BDG,and ∆EFC

• DAE=DGB=EFC = 90

• DE=BG=FC

• DGB=ECF = ADE

∆ADE~∆BDG~∆EFC

Then,

GF=BG=FC

FG^2=BG*FC