Question

In the given figure, DEFG is a square and <BAC = 90°. Show that FG^2= BG X FC​

Answer 1

Answer:

BG * FC = FG²

Step-by-step explanation:

∠B = 90° - ∠C or ∠C = 90° - ∠B

in Δ BDG

ΔD = 90° - ∠B = ∠C

& in Δ CEF

∠E = 90° - ∠C = ∠B

now comparing

Δ BDG & Δ CEF

ΔD = ∠C

∠B = ∠E

∠G = ∠F = 90°

=> Δ BDG ≈ Δ CEF

=> BD/CE = BG/ EF = DG/ FC

=> BG/ EF = DG/ FC

=> BG * FC = EF * DG

EF = DG = FG ( sides of square)

=> BG * FC = FG * FG

=> BG * FC = FG²

QED

proved