Question

. In the given figure, diagonal AC of a quadrilateral ABCD bisects the LA and 2C. Prove that AB = AD and CB
= CD​

Answer 1

Step-by-step explanation:

Draw the perpendicular by joining BD

Since they AC is bisecting then the distance between the BO and DO should be same

Assume it to be x

Then apply the sin theta formula on the right angle 4 triangles this proves it ;)

Answer 2

Answer:

Step-by-step explanation: