Question

In the given figure, Diameter
AB and a chord AC have a
common vertex. If the
length of AB=20 cm. and
AC = 12 cm. How far is AC
from the centre of the circle?​

Answer 1

Answer:

Diameter of the circle =20cm so, radius will be 10cm

AC=12cm.

so,AD =6cm. (perpendicular drawn from the centre of the circle bisects the chord)

By Pythagoras theorem on ∆ADO

AO²=AD²+OD²

SO, OD=√100-36=√64=8cm ans

Answer 2

Answer:

Answer:Hope it will help u

Answer:Hope it will help uStep-by-step explanation:

Answer:Hope it will help uStep-by-step explanation:Given :AB=20 CM & AC=12 cm

To find : The distance from centre to AC i.e DO ?

find : The distance from centre to AC i.e DO ?Solution :

find : The distance from centre to AC i.e DO ?Solution : AO=1/2×AB ; AD=1/2×AC

find : The distance from centre to AC i.e DO ?Solution : AO=1/2×AB ; AD=1/2×ACAO=1/2×20 ; AD=1/2×12

AO=10 ; AD=6

so, in right-angled triangle AOD

By Pythagoras theorem

AO²=AD²+DO²

10²=6²+DO²

100=36+DO²

100-36=DO²

64=DO²

DO=√64

DO=8CM