In the given figure, diameter
AB is 12 cm long. AB is
trisected at points P and Q.
Find the area of the shaded A
region. [Take n = 3.14 |
& Find the area of the shaded
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AP = PQ = QB = = 4 cm
Area of shaded region
= 2 [Area of semicircle with radius AW - area of semicircle with diameter AP]
= 2
= (36 - 4)
= 32 cm2
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