IN the given figure,'DO' and 'CO' are the bisectors of angle ADC and angle BCD respectively. If angle ADC = angle BCD = 60 degree and angle DAB =100 degree. Find the measure of angle DOC and angle ABC. The intersecting point is 'O'.
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The measure of ∠DOC us 120° and ∠ABC is 140°
GIVEN
'DO' and 'CO' are the bisectors of ∠ADC and ∠BCD respectively. If ∠ADC = ∠BCD = 60° and ∠DAB =100°.
TO FIND
∠DOC and ∠ABC.
SOLUTION
We can simply solve the above problem as follows;
We know that,
CO is the angle bisector of ∠BCD
Therefore,
∠BCO = ∠OCD = 1/2 ∠BCD
∠ODC = ∠OCD = 30°
In ΔOCD
∠OCD + ∠COD + ∠CDO = 180° (sum of interior angle of triangle)
30 + ∠COD + 30 = 180
∠COD = 180 - 60 = 120°
In quadrilateral ABCD
∠A + ∠B + ∠C + ∠D = 360° (sum of angles of a quadrilateral)
100 + ∠B + 120 = 360
∠B = 360-220 = 140°
∠ABC = 140°
Hence, The measure of ∠DOC us 120° and ∠ABC is 140°
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