Question

In the given figure, E and F are the centers of two identical circles. What is the ratio of area of triangle AOB to the area of triangle DOC?

A) 1 : 3 B) 1 : 9 C) 1 : 8 D) 1 : 4

Answer 1

Answer:

Step-by-step explanation:

∠AEB ≈ MED

∠AFB ≈ CFN

So,

AB = DM = CN

&

AB = MN

[As shown in fig]

AB/(DM+MN+NC)=AB/DC=1/3

So,

(Area of ∆AOB)/(Area of ∆DOC)=(AB^2)/(DC^2 )=(1/3)^2=1/9