Question

In the given figure, E, F, G, H, O and I are the mid-points
of the sides DC, BC, AB, AD, GF and AC respectively. If
ar(AOGB) = 2 cm2 and ar(ADHE = 4 cm² and BI, GF, HF
are the line segments, then the area of quadrilateral
ABCD is equal to
​

Answer 1

Answer:

Given that:- ABCD is a rectangle, E,F<G<H are the midpoints of AB,BC,CD,DA

Area of EFGH=16cm2

R.T.P   Ar of ABCD

construction:-join FH

 

Proof:-

in quad ABFH

Ar of EFH=1/2 Ar of ABFH.............1

in quad DCFH

Ar of GFH=1/2Ar ofDCFH..............2

from 1 and 2 we get

Ar of EFGH=1/2Ar of ABCD...........3

from 3  

Ar of ABCD =2 x 16 = 32cm2

Step-by-step explanation:

Answer 2

Answer:

...

Step-by-step explanation:

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