Question

In the given figure E is the mid-point of XY and EF∥YZ. If XZ = 7 cm then find XF.

Answer 1

Answer:

Refer to the above attachments.

Step-by-step explanation:

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Answer 2

Answer:

Consider ∆ADB and ∆EDF ,

$\frac{bd}{ de } = \frac{ab}{fe}$

$\frac{4}{y} = \frac{6}{10}$

$6y = 40$

$y = \frac{40}{6} = \frac{20}{3}$

$= y = 6.67cm$

Similarly , ∆ADE ~ ∆CDE .

$\frac{de}{be} = \frac{dc}{ba}$

$\frac{6.67}{10.67 } = \frac{x}{6}$

$x = 6 \times \frac{6.67}{10.67}$

$x = 3.75cm$

The values of x and y are 3.75 cm and 6.67 cm.

Hope it will help you