Question

In the given figure, EADF is a rectangle and ABC is a triangle whose vertices lie on the sides
of rectangle as shown. AE = 22, BE = 6, CF = 16 and BF = 2 then area of triangle ABC is
22
6
16 co
(A) 60 Sq. units
(C) 80 Sq. units
(B) 70 Sq. units
(D) None of these​

Answer 1

Answer:

otion ( b ) is the correct option

Answer 2

Answer:

Area - 64.99 Sq. units

Step-by-step explanation:

AB = √(AE² + BE²) = √22² + 6² = √(484 + 36) = √520 = 22.8

BC = √(BF² + FC²) = √2² + 16² = √(4 + 256) = √260 = 16.12

AC = √(AD² + CD²) =√(6+2)² + (22 - 16)² =√(8² + 6²) =√64 + 36 = 10

s = (22.8 + 16.12 + 10)/ 2 = 24.46

Area = √s.(s-a).(s-b).(s-c) = √24.46.(24.46 - 22.8).(24.46 - 16.12). (22.46 - 10)

= √24.46 x 1.66 x 8.34 x 12.46

= 64.99 Sq. units

So, answer is none of these.