Question

In the given figure, EF || HG and EF = HG. If ar(AIFG) = 28 cm2 and/
is the intersection point EG and FH, then the area of given figure is

56 cm
84 cm2
112 cm
124 cm​

Answer 1

Answer:

84cm²

Step-by-step explanation:

EF ॥ HG

EF= HG

Given ,

Area of AIFG= 28cm²

area of given figure= EFI+ FIG + HIG

= 28+ 28+28

= 84cm²

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