In the given figure, equilateral triangle ABD and triangle ACE are drawn on the side of triangle ABC. Prove that CD = BE
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Given÷∆ABD and ∆ACE are equilateral triangle
To Prove ÷ angle CAD=angle BAE
CD=BE
Proof ÷ angle CAD=angle CAB+angle BAD
Angle CAD=angle CAB+60°
(since angle CAE=60°)
angle CAD=angle CAB+angle CAE
since,angle CAE =60°
angle CAD=angle BAE
Hence,proved
In∆CADand∆BAE
BD=AD(equilateral triangle )
angle CAD=angle BAE(Proved above)
AC=AE(equilateral triangle)
By SAS,
∆CAD=~∆BAE
So,CD=BE(By CPCT)
Hence,proved
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