Question

in the given figure FB is perpendicular to DBC and AE is perpendicular to BC. Angle FBD=70°, angle EAC=25°. Find the three angles of triangle ABC​

Answer 1

angle A = 95degree

angle B = 20degree

angle C = 65degree

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Answer 2

since,
angle FBA+angleABE=90*
or, 70*+/_ABE=90*
or, /_ABE=20*
now in triangle BAE
angle B+ angle A + angle E=180*
or, 20+90+angleA=180*
or, angle A=70*
now in triangle BAC
totally Angle A= 25*+70*=95*
angleB+A+C=180*
from equation answer will be 75*