in the given figure FB is perpendicular to DBC and AE is perpendicular to BC. Angle FBD=70°, angle EAC=25°. Find the three angles of triangle ABC
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sudhanshu314:
FB is perpendicular on line DBC
than FBC=90
FBC=FBA+ABC
90=70+ABC
90-70=ABC
ABC=20
I have done that only
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angle A = 95degree
angle B = 20degree
angle C = 65degree
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since,
angle FBA+angleABE=90*
or, 70*+/_ABE=90*
or, /_ABE=20*
now in triangle BAE
angle B+ angle A + angle E=180*
or, 20+90+angleA=180*
or, angle A=70*
now in triangle BAC
totally Angle A= 25*+70*=95*
angleB+A+C=180*
from equation answer will be 75*
angle FBA+angleABE=90*
or, 70*+/_ABE=90*
or, /_ABE=20*
now in triangle BAE
angle B+ angle A + angle E=180*
or, 20+90+angleA=180*
or, angle A=70*
now in triangle BAC
totally Angle A= 25*+70*=95*
angleB+A+C=180*
from equation answer will be 75*
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