Question

in the given figure, find ​

Answer 1

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

first prove that both triangles a congruent -∆DAC and ∆CAB

1-DC is equal to AB(given)

2-AD is equal to BC (given)

3-line AC is the common in both Triangle (given)

by s s s criteria we can say that both triangle are congruent .

By C.P.C.T

1-ACB=CAD

2-B=D

3-ACD=CAB

SO, 1-B=110=D

2-ACB=CAD=30

3-ACD=110+30-180=40=CAB

HOPE THIS ANSWER IS HELPFUL FOR YOU❤❤❤

Answer 2

Answer:

<dac =<ACB ( alternate angle )

so, <dac = 30°

given that AB parallel to DC

so, <a + <d = 180°

<cab = 180°- 110°- 30°

<cab = 40°

<cab = <DCA ( alternate angle )

<DCA = 40°

<d = <b ( opposite sides of a parallelogram are equal )

<b= 110°