Math, asked by viraj84789, 7 months ago

In the given figure, find:-
(a) \angleYRQ

(b) \anglePRQ

Attachments:

Answers

Answered by hridoyboy
0

Answer:

a)YRQ=130

b)PRQ=50

hope it will help you.

Answered by ƦαíηвσωStαƦ
16

\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}

\sf{\underline{\green{AnswEr:-}}}

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  • \angleYRQ = 130°

  • \anglePRQ = 50°

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\sf{\underline{\green{Find:-}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

  • \angleYRQ = ?

  • \anglePRQ = ?

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\sf{\underline{\green{Explanation:-}}}

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(a) \angleYRQ

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle YRQ = \angle P + \angle Q}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle YRQ = 60\degree + 70 \degree }

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle YRQ = 130\degree}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\rule{200}{2}

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(b) \anglePRQ

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle PRQ = 180\degree  - (\angle P + \angle Q)}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle PRQ = 180\degree - (60\degree + 70\degree)}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle PRQ = 180\degree - 130\degree}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longrightarrow \sf {\angle PRQ = 50\degree}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

  • \angleYRQ = 130°

  • \anglePRQ = 50°

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\rule{200}{2}

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