in the given figure
find AD
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i can't understand ur oversta bhro and sis
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cutting in short.....
given AC = BC
<ACB = 180 - <ACD = 180 - 60 = 120
since AC = BC
< ABC = < BAC = (180 - 120)/2 = 60/2 = 30°
in ∆ ADB
sin 30° = AD/AB
1/2 = AD/100
AD = 100/2
AD = 50 m
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