in the given figure . find angle RQU.
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Angle equals is 25 degrees
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Answer: < RQU = 25°
Solution:
In ∆ SUT
< SUT = 45° [ From angle sum property of triangle]
Now, < SUT + < TUQ + < QUR = 180° [Linear Pair ]
45°+ 70° + < QUR = 180°
< QUR = 180° -115°
< QUR= 65°
Now in ∆ QUR
< URQ + < RQU + < QUR = 180° [Angle sum property of triangle ]
< RQU = 180°-65°-90°
< RQU = 25°
Hope it helps you.
Solution:
In ∆ SUT
< SUT = 45° [ From angle sum property of triangle]
Now, < SUT + < TUQ + < QUR = 180° [Linear Pair ]
45°+ 70° + < QUR = 180°
< QUR = 180° -115°
< QUR= 65°
Now in ∆ QUR
< URQ + < RQU + < QUR = 180° [Angle sum property of triangle ]
< RQU = 180°-65°-90°
< RQU = 25°
Hope it helps you.
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