Question

In the given figure, find angle x if AB CD || .​

Answer 1

Step-by-step explanation:

Draw an imaginary line through point E.let the line be PQ

and then CD parallel to PQ CE is transversal

angle DCE=angle CEP=110°

now,angle CEP+angle CEQ =180°

that means angle CEQ=70°

AB is parallel to PQ AE is transversal

angle BAE= angle AEQ=100°

angle AEQ= angle AEC+angle CEQ

100°=X°+70°

X°=30°

Answer 2

Answer:

Step-by-step explanation:

. From figure, AB‖CD.

So, ∠DCF = ∠AFC

    ∠AFC = 110 degree (since ∠DCF = 110 degree )

     Therefore, ∠AFE =180-∠AFC

                      ∠AFE = 70° and

∠EAF = 180-∠BAE

∠EAF = 180-100 =80°.

From ∆∠EAF + ∠AFE+∠AEF = 180

               80+70+∠AEF =180

∠AEF = x = 30°.