Question

in the given figure , find ∆BAC find the answer​

Answer 1

ABC is isosceles. So angle A = angle B = 3x

By angle sum property.

60 + 6x = 180

x = 20

So angle A = angle B = 60

Similarly angle B’A’C = 2x + 20

= 40 + 20 = 60

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Answer 2

Answer:

let the center of the triangle be O.

BO=OC(same radii)

then, ∠OBA=∠OAB(angles opposite to same sides)

∠OBA+OAB+∠AOB=180°(angle sum property of triangles)

2∠OAB+80°=180°

∠OAB=(180-80)/2

∠OAB=50°

Now similarly,

AO=CO(same radii)

∠OAC=∠OCA(angles opposite to equal sides)

∠AOC+∠OAC+∠ACO=180°(angle sum property of triangles)

2∠OAC+∠AOC=180°

2∠OAC+120°=180°

∠OAC=(180-120)/2

∠OAC=30°

∠BAC=∠OAB+∠OAC=50°+30°

∠BAC=80°

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hope it helps...