Question

In the given figure, find <a,<b,<c,<d​

Answer 1

Answer:

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Step-by-step explanation:

Here, AOB,COD,EOF are triangles.

Then by angle sum property,

∠a+∠b+∠AOB=180o...(i),

∠c+∠d+∠COD=180o...(ii)

and ∠e+∠f+∠EOF=180o...(iii).

Also, AOB,COD and EOF are straight lines.

Then, ∠EOF=∠BOC    ...[Vertically opposite angles].

So, ∠AOB+∠COD+∠BOC(=∠EOF)=180o...(iv)  ...[Straight line].

Then, (i),(ii) and (iii),

∠a+∠b+∠AOB+∠c+∠d+∠COD+∠e+∠f+∠EOF=180o×3=540o

⟹ ∠a+∠b+∠c+∠d+∠e+∠f+∠AOB+∠COD+∠EOF=540o  ....[Substitute (iv)]

⟹ ∠a+∠b+∠c+∠d+∠e+∠f+180o=540o

⟹ ∠a+∠b+∠c+∠d+∠e+

Answer 2

Answer:

Answer:

a=75°

b=75

c=60

d=110

Step-by-step explanation:

a (verticaally opposite angle)

b(alternate angle)

c= 180-120(cointerior angle)

d=180-60 (straight line)

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