Question

in the given figure find tanP and cotQ​

Answer 1

hypothenuse^2 = perpendicular^2 + base^2

=) base PR = 1

Tan P = perpendicular/base= 1/1 =1

Cot Q= base/hypotenuse= 1/√2

Thus TanP= 1 and Cot Q= 1/√2 (ANS)

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Answer 2

Answer:

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