In the given figure, find the area of parallelogram ABCD, if the area of shaded triangle is 9cm squared. Triangles base =3cm and Parallelogram base =4cm
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Given, Area of shaded portion =9sq.cm
Base of triangle =3cm
Now, area of triangle=9,
⇒9=
2
1
×3×h
⇒h=
3
18
⇒h=6cm
Area of parallelogram =Base x Height=BC×h
=(3+4)×6=7×6=42cm
2
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