Question

In the given figure find the area of the path.
Please Answer
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Answer 1

hey mate!

area of outer rectangle i.e ABCD = l × b = 150 × 110 = 16500 cm²

length of inner rectangle EFGH = 150 - ( 5+5) = 150 - 10 = 140cm

breadth of inner rectangle EFGH = 110 - ( 5+5) = 110 - 10 = 100cm

so, area of inner rectangle EFGH = l × b = 140 × 100 = 14000 cm²

Area of path = outer rectangle area - inner rectangle area

= 16500 - 14000 = 2500 cm²

hope this helps you

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thanks❤❤

Answer 2

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To Find:

• Area of the path

Solution:

To calculate the area of the path, we can either calculate the area of the whole figure and then subtract the white part, or we can divide the path into rectangles so as to calculate area of each one of them and then add them.

Method 1:

=> Area of the whole figure = Length * breadth

=> Area of the whole figure = 150 * 110

=> Area of the whole figure = 16500cm^2 -----(1)

=> Area of white part = Length * breadth

=> Area of white part = (150-10) * (110-10)

=> Area of white part = 140 * 100

=> Area of white part = 14000cm^2 -----(2)

Now,

=> Area of the path = (Area of the whole figure) - (Area of white part)

from (1) & (2)

=> Area of the path = 16500 - 14000

=> Area of the path = 2500cm^2

Method 2:

(Refer the attachment for the division of the path into rectangles)

=> Area of Rectangle 1 = Length * Breadth

=> Area of Rectangle 1 = 150 * 5

=> Area of Rectangle 1 = 750cm^2

=> Area of Rectangle 2 = Length * Breadth

=> Area of Rectangle 2 = 100 * 5

=> Area of Rectangle 2 = 500cm^2

But,

Area of Rectangle 1 = Area of Rectangle 3 = 750 cm^2

AND

Area of Rectangle 2 = Area of rectangle 4 = 500 cm^2

So,

=> Area of Path = 2(Area of Rectangle 1) + 2(Area of Rectangle 2)

=> Area of path = 2(750) + 2(500)

=> Area of path = 1500 + 1000

=> Area of path = 2500cm^2

Hope it helps!!!!