Question

In the given figure, find the area of the shaded portion u 2 m 3 m 121 15 m​

Answer 1

Answer:

$Area of shaded region=arΔABC−arΔDBCarΔABC=s(s−a)(s−b)(s−c)s=2a+b+c=2122+22+120=132m∴arΔABC=132(132−122)(132−22)(132−120)=132×10×110×12=11×12×10×10×11×12=10×11×12=1320m2arΔBDC=s(s−a)(s−−b)(s−c)s=2a+b+c=236+22+24=36m∴arΔBDC=36(36−26)(36−22)(36−24)=36×10×14×12=12×3×2×5×2×7×12=2×12105=24×10.24=245.76m2</p><p>∴ area of shaded region=1320−245.76=1074.24m2≈1074m2</p><p></p><p>$