Question

In the given figure, find the area of the trapezium ABCD.​

Answer 1

Answer:

Answer is 96

Step-by-step explanation:

Add all the sizes

Answer 2

Answer:

297.5 cm^2

Step-by-step explanation:

Area of a trapezium =$\frac{(a+b)h}{2}$

Here,

a = AB = 15cm

b = DC = 40cm

h = AD

Use Pythagoras’ Theorem to find the height:

h = $\sqrt{41^{2}- 40^{2}$

h = $\sqrt{1681-1600}$

h = $\sqrt{81}$

h = 9 cm

Substitute a, b and h into the formula

Area of a trapezium = $\frac{(15+40)9}2$

Area = 55 x 9 divided by 2

Area = $\frac{595}{2}$ = 297.5$cm{2}$

Hope this helps,

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