Question

in the given figure ,find the equivalent resistance between P and Q. If- C1, C3, C4 and C5 are each of 4micro farad and C2=10micro farad

Answer 1

Check the attachment

Answer 2

Answer: $C = 4\mu F$

Explanation:

Given that,

$C_{1}=C_{3} = C_{4} = C_{5} = 4 \mu F$

$C_{2} = 10\mu F$

According to figure;

This circuit  follows balance whetstone bridge.

So, $C_{2}$ neglects.

Now, $C_{4} and C_{3}$ are in series.

So, $\dfrac{1}{C'} =\dfrac{1}{4} + \dfrac{1}{4}$

$\dfrac{1}{C'} = \dfrac{1}{2}$

$C' = 2 \mu F$

Now, $C_{1} and C_{5}$ are in series.

So, $\dfrac{1}{C''} =\dfrac{1}{4} + \dfrac{1}{4}$

$\dfrac{1}{C''} = \dfrac{1}{2}$

$C'' = 2 \mu F$

Now, C' and C'' are in parallel

Then, the equivalent resistance between P and Q is

$C = C'+C''$

$C = 2\mu F+2\mu F$

$C = 4\mu F$

Hence, the equivalent resistance between P and Q is $C = 4\mu F$.