Question

in the given figure, find the height of the building.
BC = 50m
angle C = 60°​

Answer 1

Answer:

$\tan60 {}^{0} = \frac{p}{b} = \frac{ab}{bc}$

$\tan60 {}^{0} = \frac{ab}{50}$

$\sqrt{3} = \frac{ab}{50}$

$ab = 50 \sqrt{3}$

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Answer 2

Answer:

50√3. please follow me