In the given figure find the length of the chord AB
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√(10) 2- (6) 2= √100-36=√64=8
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AL = √(100-36) = √64 = 8
So, LB = 8 cm (As AL = LB since O is centre and OL is line from centre which will be perpendicular on AB as well as Bisect AB)
Therefore, AB = (8+8) cm = 16 cm
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