Question

in the given figure find the measur of angle B' A' C'​

Answer 1

Answer:

B',A',C' angles respectively are

Step-by-step explanation:

by SAS property triangle ABC congruent to A'B'C'

By CPCT angle BAC=B'A'C'

3x=2x+28

3x-2x=28

x=28

B'=60⁰

A'=2x+28

(2×28)+28

56+28

84 =B'

C'=180⁰-(84⁰+60⁰)=36⁰

Answer 2

Answer:

Thus ∠B¹A¹C¹=60°

Step-by-step explanation:

In the ΔABC and ΔA¹B¹C¹

AB= A¹B¹

∠B=∠B¹=60°

BC=B¹C¹=5 cm

So ΔABC≅ ΔA¹B¹C¹

SO ∠A=∠A¹

3x=2x+20°

x=20°

Thus ∠B¹A¹C¹=2x+20

=2*20+20

=60°