In the given figure find the measure of angleB is 60* A'C
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∠ACB+100
∘
=180
∘
∠ACB=180
∘
−100
∘
=80
∘
∠BAC=20
∘
(Vertically opposite angle)
So, In triangle ABC, by angle sum property; ∠BAC+∠ACB+∠ABC=180
∘
Thus, ∠ABC=180
∘
−80
∘
−20
∘
=80
∘
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