In the given figure, find the natural frequency of the system. If m = 10 kg attached at one end of weightless rod and k = 1000 N/m
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Given:
m = 10 kg attached at one end of the weightless rod and k = 1000 N/m
To find:
Find the natural frequency of the system.
Solution:
From given, we have the data as follows.
The mass, m = 10 kg attached at one end of the weightless rod and the spring constant, k = 1000 N/m
The natural frequency of the system is,
f = 1/2π √[k/m]
substitute the values in the above equation.
f = 1/2π √[1000/10]
continue the further calculation
f = 1/2π √[100]
f = 1/2π (10)
f = 5/π
Therefore, the value of the natural frequency is, 1.59 Hz.
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