Question

In the given figure, find the shaded area if angle in sector OPAQ is 60˚ and PQB is a semicircle​

Answer 1

The centre of arc PMQ is O.OP = OQ = 10 cm and m POQ = 60^2 . Find the area of the shaded portion.(Given pi = 3.14, √(3) = 1.73) ...

For a Segment PMQ,radius r = 10cm Measure of theta = 60^∘ Area of Segment PMQ = r^2 [pitheta/360 - sintheta/2 ] = 10^2 [3.14 × 60/360 - sin60/2 ...

Answer 2

Answer:

In the given figure, find the shaded area if angle in sector OPAQ is 60˚ and PQB is a semicircle