Question

In the given figure, find
the sum of area of the
smaller circles, if the two
smaller circles are of the
same radius and their
centres lie on the diameter
of the bigger circle whose
radius is 28 cm.​

Answer 1

Answer:

radius of bigger circle =28cm

radius of smaller circle =28/2=14

sum of area of smaller circles =308

$sum \: of \: area \: of \: smaller \:circles \\ = \pi {r}^{2} + \pi {r}^{2} \\ (radius \: same) ( radius = 7cm) \\ = 2\pi {r}^{2} \\ = 2 \times \frac{22}{7} \times 7 \times 7 \\ = 44 \times 7 \\ =30 8 {cm}^{2}$