Question

in the given figure find the vale of ce​

Answer 1

Answer:

$CE = \frac{12}{ \sqrt{3} } = 4 \sqrt{3}$

Step-by-step explanation:

we know that

$\sin( \alpha ) = \frac{hight}{hypotenous}$

then

sin 60= BC/CE

==>

$\frac{ \sqrt{3} }{2} = \frac{6}{ CE}$

==>

$CE = \frac{12}{ \sqrt{3} } = 4 \sqrt{3}$

Answer 2

Answer:

CE=12cm

Step-by-step explanation:

cos60=BC/CE

THEREFORE 1/2=6/CE

THEREFORE CE=12cm